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Engineering ToolBox > Entropy in Compressible Gas Flow

Calculating entropy in compressible gas flow

Entropy change in compressible gas flow can be expressed as

ds = cv ln(T2 / T1) + R ln(ρ1 / ρ2) (1)

or

ds = cp ln(T2 / T1) - R ln(p2 / p1) (2)

where

ds = entropy change

cv = specific heat capacity at a constant volume process

cp = specific heat capacity at a constant pressure process

T = absolute temperature

R = individual gas constant

ρ = density of gas

p = absolute pressure

Example - Entropy Change in an Air Heating Process

Air - 10 kg - is heated at constant volume from temperature 20 oC and 101325 N/m2 to a final pressure of 405300 N/m2.

The final temperature in the heated air can be found using the ideal gas equation:

p v = R T (3)

where

v = volume

The ideal gas equation (3) can be transformed to express the volume before heating:

v1 = R T1 / p1 (4)

Since v1 = v2 the ideal gas equation (3) after heating can be expressed as:

p2 v1 = R T2 (5)

or transformed to express the final temperature:

T2 = p2 v1 / R (6)

Combining (5) and (6):

T2 = p2 (R T1 / p1) / R

    = p2 T1 / p1 (7)

    = (405300 N/m2) (273 + 20 K) / (101325 N/m2)

    = 1172 K - the final temperature

The change in entropy can be expressed by (2)

ds = cp ln(T2 / T1) - R ln(p2 / p1)

ds = (1.05 kJ/kg.K) ln(1172 K / 293 K) - (0,33 kJ/kg.K) ln(405300 N/m2 / 101325 N/m2)

    = 1 kJ/kg.K

Total change in entropy:

dS = (1 kJ/kg.K) (10 kg) = 10 kJ/K

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