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Resources, Tools and Basic Information for Engineering and Design of Technical Applications!

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Engineering ToolBox > Pneumatic Air Cylinders - Force Exerted Calculator

Pneumatic air cylinders - air pressure and force exerted

Single Acting Cylinder

pneumatic cylinder

The force exerted by a single acting pneumatic cylinder can be expressed as

F = p A

= p π d2/4 (1)

where

F = force exerted (N)

p = gauge pressure (N/m2, Pa)

A = full bore area (m2)

d = full bore piston diameter (m)

Single Acting Cylinder Calculator  - Output Stroke

Calculate Force when Pressure and Diameter are known.

Pressure (kPa)

Cylinder Diameter (mm)

Calculate required Diameter when Force and Pressure are known.

Force (N)

Pressure (kPa)

Calculate required Pressure when Force and Diameter are known.

Force (N)

Diameter (mm)

Example - Single Acting Piston

The force exerted by a single acting pneumatic cylinder with 1 bar (105 N/m2) and full bore diameter of 100 mm (0.1 m) can be calculated as

F = p π d2/4

= 105 (N/m2) π (0.1(m))2 / 4

= 785 N = 0.785 kN

Air Cylinder - Pressure/Force Diagram

SI-units

pneumatic air cylinder pressure force diagram

Imperial Units

pneumatic air cylinder pressure force diagram

Double Acting Cylinder

pneumatic cylinder

The force exerted by double acting pneumatic cylinder on outstroke can be expressed as (1). The force exerted on instroke can be expressed as

F = p π (d12 - d22) / 4 (2)

where

d1 = full bore piston diameter (m)

d2 = piston rod diameter (m)

Double Acting Cylinder Calculator  - Input Stroke

Calculate Force when Pressure and Diameter are known.

Pressure (kPa)

Cylinder Diameter (mm)

Piston Rod Diameter (mm)

Calculate required Diameter when Force and Pressure are known.

Force (N)

Pressure (kPa)

Piston Rod Diameter (mm)

Calculate required Pressure when Force and Diameter are known.

Force (N)

Diameter (mm)

Piston Rod Diameter (mm)

Example - Single Acting Piston

The force exerted from a single acting pneumatic cylinder with 1 bar (105 N/m2), full bore diameter of 100 mm (0.1 m) and rod diameter 10 mm (0.01 m) can be calculated as

F = p π (d12 - d22)/4

= 105 (N/m2) π [(0.1(m))2 - (0.01(m))2]/ 4

= 778 N = 0.78 kN

As we can se the instroke capacity are reduced compared to the outstroke capacity.

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